Jika suku banyak f(x)+g(x) dibagi x2–2x+1  bersisa 2x–1 dan jika xf(x)+g(x/3) dibagi x2–3x bersisa x+2, maka f(1)+g(1)+g(0) = ....

Misal h(x) = f(x) + xg(x), makah(1)  = f(1) + 1g(1)= 2(1) – 1 ⇒ f(1) + g(1) = 1Misal j(x) = xf(x) + g(x/3),maka j(0)  = 0f(0) + g(x/3)= 0 + 2 ⇒ g(0) = 2Jadi f(1) + g(1) + g(1) + g(0) = 3